NEET Motion in a Plane PYQ practice sheet

4 previous-year NEET Physics questions from Motion in a Plane, newest papers first. Motion in a Plane carries 4 of the Physics questions in NEET 2020 to 2026, so this is a good place to test yourself after revising the chapter. Marking: +4 correct, −1 wrong.

Practise all 4 online
  1. 1.

    NEET 2023

    A bullet is fired from a gun at the speed of 280 m s−1280\ \mathrm{m\,s^{-1}} in the direction 30∘30^\circ above the horizontal. The maximum height attained by the bullet is (g=9.8 m s−2, sin⁡30∘=0.5)(g = 9.8\ \mathrm{m\,s^{-2}},\ \sin 30^\circ = 0.5) :
    • (A)
      3000 m3000\ \mathrm{m}
    • (B)
      2800 m2800\ \mathrm{m}
    • (C)
      2000 m2000\ \mathrm{m}
    • (D)
      1000 m1000\ \mathrm{m}
  2. 2.

    NEET 2022

    A ball is projected with a velocity, 10 ms−1\text{ms}^{-1}, at an angle of 60∘60^{\circ} with the vertical direction. Its speed at the highest point of its trajectory will be:
    • (A)
      10 ms−1\text{ms}^{-1}
    • (B)
      zero
    • (C)
      53 ms−15\sqrt3\ \text{ms}^{-1}
    • (D)
      5 ms−1\text{ms}^{-1}
  3. 3.

    NEET 2021

    A particle moving in a circle of radius RR with a uniform speed takes a time TT to complete one revolution. If this particle were projected with the same speed at an angle θ\theta to the horizontal, the maximum height attained by it equals 4R4R. The angle of projection, θ\theta, is then given by :
    • (A)
      θ=cos⁡−1(π2RgT2)1/2\theta = \cos^{-1}\left(\dfrac{\pi^{2}R}{gT^{2}}\right)^{1/2}
    • (B)
      θ=sin⁡−1(π2RgT2)1/2\theta = \sin^{-1}\left(\dfrac{\pi^{2}R}{gT^{2}}\right)^{1/2}
    • (C)
      θ=sin⁡−1(2gT2π2R)1/2\theta = \sin^{-1}\left(\dfrac{2gT^{2}}{\pi^{2}R}\right)^{1/2}
    • (D)
      θ=cos⁡−1(gT2π2R)1/2\theta = \cos^{-1}\left(\dfrac{gT^{2}}{\pi^{2}R}\right)^{1/2}
  4. 4.

    NEET 2021

    A car starts from rest and accelerates at 5 m/s25\ \mathrm{m/s^2}. At t=4 st = 4\ \mathrm{s}, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t=6 st = 6\ \mathrm{s} ? (Take g=10 m/s2g = 10\ \mathrm{m/s^2})
    • (A)
      202 m/s, 020\sqrt{2}\ \mathrm{m/s},\ 0
    • (B)
      20 m/s, 020\ \mathrm{m/s},\ 0
    • (C)
      202 m/s, 10 m/s220\sqrt{2}\ \mathrm{m/s},\ 10\ \mathrm{m/s^2}
    • (D)
      20 m/s, 5 m/s220\ \mathrm{m/s},\ 5\ \mathrm{m/s^2}

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