NEET Electric Charges and Fields PYQ practice sheet

4 previous-year NEET Physics questions from Electric Charges and Fields, newest papers first. Electric Charges and Fields carries 7 of the Physics questions in NEET 2020 to 2026, so this is a good place to test yourself after revising the chapter. Marking: +4 correct, −1 wrong.

Practise all 5 online
  1. 1.

    NEET 2023

    An electric dipole is placed at an angle of 30∘30^\circ with an electric field of intensity 2×105 N C−12\times10^{5}\ \mathrm{N\,C^{-1}}. It experiences a torque equal to 4 N m4\ \mathrm{N\,m}. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm2\ \mathrm{cm}.
    • (A)
      2 mC2\ \mathrm{mC}
    • (B)
      8 mC8\ \mathrm{mC}
    • (C)
      6 mC6\ \mathrm{mC}
    • (D)
      4 mC4\ \mathrm{mC}
  2. 2.

    NEET 2022

    Two point charges −q-q and +q+q are placed at a distance of LL, as shown in the figure. The magnitude of electric field intensity at a distance RR (R≫LR\gg L) varies as:
    • (A)
      1R6\dfrac{1}{R^6}
    • (B)
      1R2\dfrac{1}{R^2}
    • (C)
      1R3\dfrac{1}{R^3}
    • (D)
      1R4\dfrac{1}{R^4}
  3. 3.

    NEET 2021

    A dipole is placed in an electric field as shown. In which direction will it move ? Figure: the electric field lines diverge from a point on the left and spread out towards the right, so the field is stronger on the left and weaker on the right. The field E⃗\vec{E} points to the right along the central line. A dipole lies along the central line with the charge +q+q on the left and the charge −q-q on its right. Question diagram
    • (A)
      towards the right as its potential energy will increase.
    • (B)
      towards the left as its potential energy will increase.
    • (C)
      towards the left as its potential energy will decrease.
    • (D)
      towards the right as its potential energy will decrease.
  4. 4.

    NEET 2020

    A spherical conductor of radius 1010 cm has a charge of 3.2×10−73.2\times10^{-7} C distributed uniformly. What is the magnitude of electric field at a point 1515 cm from the centre of the sphere? (14πϵ0=9×109 N m2/C2)\left(\frac{1}{4\pi\epsilon_0}=9\times10^{9}\ \mathrm{N\,m^2/C^2}\right)
    • (A)
      1.28×1041.28\times10^{4} N/C
    • (B)
      1.28×1051.28\times10^{5} N/C
    • (C)
      1.28×1061.28\times10^{6} N/C
    • (D)
      1.28×1071.28\times10^{7} N/C

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