Conic Sections: JEE Mains 2022 June 29 Shift 1

Hard· Parabola· +4 / −1
Let PQPQ be a focal chord of the parabola y2=4xy^2=4x such that it subtends an angle of π2\dfrac\pi2 at the point (3,0)(3,0). Let the line segment PQPQ be also a focal chord of the ellipse E:x2a2+y2b2=1E:\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1, a2>b2a^2>b^2. If ee is the eccentricity of the ellipse EE, then the value of 1e2\dfrac{1}{e^2} is equal to :
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