Conic Sections: JEE Mains 2022, June 28 - Shift 1

Hard· Hyperbola· +4 / −1
For the hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1, the eccentricity is e=52e=\sqrt{\dfrac52} and the length of the latus rectum is 626\sqrt2. If y=2x+cy=2x+c is a tangent to the hyperbola, find cc.
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