Conic Sections: JEE Mains 2022 June 29 Shift 2

Medium· Circle· +4 / −1
Let a triangle ABCABC be inscribed in the circle x2−2 (x+y)+y2=0x^2-\sqrt2\,(x+y)+y^2=0 such that ∠BAC=π2\angle BAC=\dfrac\pi2. If the length of side ABAB is 2\sqrt2, then the area of the △ABC\triangle ABC is equal to :
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