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JEE Main Maths Coordinate Geometry 2027: Straight Lines, Circles & Conic Sections

Straight line forms, angle between lines, circle equations and the standard forms of parabola, ellipse and hyperbola, taught with worked examples.

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October 1, 2026

JEE Main Maths Coordinate Geometry 2027: Straight Lines, Circles & Conic Sections

Coordinate Geometry rewards a layered approach: lines first, since circles and conics both lean on line concepts, then circles, then the three conic sections. It is one of the highest-yield chapters in JEE Main Maths, and its formulas stay useful throughout the paper, from vectors to calculus.

Every conic section answers the same question: what is the locus of points satisfying one clean geometric rule?

Chapter at a Glance

SnapshotDetail
NTA unitUnit 10 of 14: Co-ordinate Geometry
Priority (trend-based)High
Typical question styleLine and circle numericals plus conic section parameter calculations
Best first stepMaster the straight line toolkit, then circles, then conics

Priority reflects past-paper trends, not an official NTA weightage.

What the NTA Syllabus Covers

  • Cartesian coordinates, distance formula, section formula, locus and its equation, slope, parallel and perpendicular lines, intercepts
  • Straight line: forms of equations of a line, intersection of lines, angle between two lines, concurrence of three lines, distance of a point from a line, centroid, orthocentre and circumcentre
  • Circle: standard and general forms, radius and centre, circle through diameter endpoints, intersection with a line
  • Conic sections: equations of parabola, ellipse and hyperbola in standard forms

Master These Topics

1. The Straight Line Toolkit

Distance formula: (x2−x1)2+(y2−y1)2\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. Section formula for a point dividing (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) in ratio m:nm:n: (mx2+nx1m+n,my2+ny1m+n)\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right).

Angle between two lines with slopes m1,m2m_1, m_2: tan⁡θ=∣m1−m21+m1m2∣\tan\theta = \left\lvert\dfrac{m_1 - m_2}{1 + m_1m_2}\right\rvert. Lines are parallel when m1=m2m_1 = m_2 and perpendicular when m1m2=−1m_1m_2 = -1.

Distance of a point (x1,y1)(x_1, y_1) from the line ax+by+c=0ax + by + c = 0: ∣ax1+by1+c∣a2+b2\dfrac{\lvert ax_1+by_1+c\rvert}{\sqrt{a^2+b^2}}.

Three lines aix+biy+ci=0a_ix + b_iy + c_i = 0 (for i=1,2,3i=1,2,3) are concurrent when the determinant of their coefficients is zero.

Worked example: Lines with slopes 22 and −13-\tfrac{1}{3}: since 2×(−13)=−23≠−12 \times (-\tfrac{1}{3}) = -\tfrac{2}{3} \ne -1, they are not perpendicular. tan⁡θ=∣2−(−1/3)1+2(−1/3)∣=∣7/31/3∣=7\tan\theta = \left\lvert\dfrac{2 - (-1/3)}{1 + 2(-1/3)}\right\rvert = \left\lvert\dfrac{7/3}{1/3}\right\rvert = 7.

2. Circles

Standard form: (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2. General form: x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0, with centre (−g,−f)(-g,-f) and radius g2+f2−c\sqrt{g^2+f^2-c}.

Worked example: For x2+y2−4x+6y−12=0x^2 + y^2 - 4x + 6y - 12 = 0, we get g=−2,f=3,c=−12g=-2, f=3, c=-12, so centre (2,−3)(2,-3) and radius 4+9+12=5\sqrt{4+9+12} = 5.

If the endpoints of a diameter are (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2), the circle's equation is (x−x1)(x−x2)+(y−y1)(y−y2)=0(x-x_1)(x-x_2) + (y-y_1)(y-y_2) = 0.

3. Conic Sections

ConicStandard formKey relationEccentricity
Parabolay2=4axy^2 = 4axFocus (a,0)(a,0), directrix x=−ax=-ae=1e = 1
Ellipsex2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1c2=a2−b2c^2 = a^2 - b^2e=c/a<1e = c/a \lt 1
Hyperbolax2a2−y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1c2=a2+b2c^2 = a^2 + b^2e=c/a>1e = c/a \gt 1

For the ellipse, the foci are (±c,0)(\pm c, 0) and every point PP on the curve satisfies PF1+PF2=2aPF_1 + PF_2 = 2a.

For this ellipse, $a = 5$, $b = 3$, so $c = 4$ and every point on the curve has $PF_1 + PF_2 = 2a = 10$.
For this ellipse, $a = 5$, $b = 3$, so $c = 4$ and every point on the curve has $PF_1 + PF_2 = 2a = 10$.

Worked example (ellipse): For x225+y29=1\dfrac{x^2}{25} + \dfrac{y^2}{9} = 1, a=5a=5, b=3b=3, so c=25−9=4c = \sqrt{25-9} = 4 and e=4/5e = 4/5.

Worked example (parabola): y2=8xy^2 = 8x gives 4a=84a = 8, so a=2a = 2: focus (2,0)(2,0), directrix x=−2x = -2.

Worked example (hyperbola): x216−y29=1\dfrac{x^2}{16} - \dfrac{y^2}{9} = 1 gives c=16+9=5c = \sqrt{16+9}=5, so e=5/4e = 5/4.

Trap: For a hyperbola, c2=a2+b2c^2 = a^2 + b^2 (addition), while for an ellipse c2=a2−b2c^2 = a^2 - b^2 (subtraction). Mixing these up is the most common slip in this section.

Common Traps to Avoid

  • Using c2=a2−b2c^2 = a^2 - b^2 for a hyperbola instead of c2=a2+b2c^2 = a^2 + b^2.
  • Forgetting the absolute value or the denominator when applying the point-to-line distance formula.
  • Reading the centre of a circle directly as (g,f)(g, f) instead of (−g,−f)(-g, -f).
  • Assuming perpendicular lines whenever slopes look different, without checking m1m2=−1m_1m_2 = -1.

60-Second Revision Sheet

  • tan⁡θ=∣m1−m21+m1m2∣\tan\theta = \left\lvert\dfrac{m_1-m_2}{1+m_1m_2}\right\rvert; distance =∣ax1+by1+c∣a2+b2= \dfrac{\lvert ax_1+by_1+c\rvert}{\sqrt{a^2+b^2}}
  • Circle centre (−g,−f)(-g,-f), radius g2+f2−c\sqrt{g^2+f^2-c}
  • Ellipse c2=a2−b2c^2 = a^2-b^2; hyperbola c2=a2+b2c^2=a^2+b^2; parabola focus (a,0)(a,0)
  • Eccentricity: parabola 11, ellipse <1\lt 1, hyperbola >1\gt 1

Your Study Plan

  1. Day 1: distance, section formula, straight line forms and angle between lines.
  2. Day 2: distance from a line, concurrency and triangle centres.
  3. Day 3: circle equations, general form and tangency conditions.
  4. Day 4: parabola, ellipse and hyperbola parameters, timed mixed set.

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Frequently Asked Questions

How do I find the centre and radius from the general equation of a circle?

Write it as x2+y2+2gx+2fy+c=0x^2+y^2+2gx+2fy+c=0, then the centre is (−g,−f)(-g,-f) and the radius is g2+f2−c\sqrt{g^2+f^2-c}.

What is the key difference between the ellipse and hyperbola relations?

For an ellipse c2=a2−b2c^2 = a^2 - b^2 (so c<ac \lt a and e<1e \lt 1), while for a hyperbola c2=a2+b2c^2 = a^2 + b^2 (so c>ac \gt a and e>1e \gt 1).

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