Medium· Area between two curves· +4 / −1The area enclosed by y2=8xy^2=8xy2=8x and y=2 xy=\sqrt2\,xy=2x that lies outside the triangle formed by y=2 xy=\sqrt2\,xy=2x, x=1x=1x=1, y=22y=2\sqrt2y=22, is equal to :A1626\dfrac{16\sqrt2}{6}6162B1126\dfrac{11\sqrt2}{6}6112C1326\dfrac{13\sqrt2}{6}6132D526\dfrac{5\sqrt2}{6}652Check answerJust show me the answer
