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Application of Integrals: JEE Mains 2022, June 28 - Shift 1

Medium· Area between two curves· +4 / −1

Find the area of the region defined by

y^2\le8x

,

y\ge\sqrt{2x}

and

x\le1

.

Practise more Application of Integrals PYQs

The area enclosed by y^2=8x and y=2\,x that lies outside the triangle formed by y=2\,x , x=1 , y=22 , is equal to :
JEE Mains 2022 June 29 Shift 1 · Medium
If _0^2(√(2x)-√(2x-x^2))dx=_0^1(1-√(1-y^2)-(y^2)/(2))dy+_1^2(2-(y^2)/(2))dy+I , then I equals :
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