Thermodynamics: JEE Mains 2024 1st Feb Shift 1

Easy· Heat capacity and calorimetry· +4 / −1
We have a mixture of gases having 2 moles of monoatomic gas (Cv,m=3R2C_{v,m}=\frac{3R}{2}) and 6 moles of diatomic gas (Cv,m=5R2C_{v,m}=\frac{5R}{2}). Find out molar heat capacity (CvmC_{vm}) of the mixture.
Practise more Thermodynamics PYQs

About this question

  • Previous-year question from JEE Mains 2024 1st Feb Shift 1.
  • Tagged easy difficulty.