Permutations and Combinations: JEE Mains 2024 1st Feb Shift 1

Hard· Distribution problems· +4 / 0
The number of solution of equation x+2y+3z=42x+2y+3z=42 and x,y,z∈Zx,y,z\in Z and x,y,z≥0x,y,z\ge0 is
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About this question

  • Previous-year question from JEE Mains 2024 1st Feb Shift 1.
  • Tagged hard difficulty.