Medium· Limits of functions and standard limits· +4 / −1The value of limx→1(x2−1)sin2(πx)x4−2x3+2x−1\displaystyle\lim_{x\to1}\dfrac{(x^2-1)\sin^2(\pi x)}{x^4-2x^3+2x-1}x→1limx4−2x3+2x−1(x2−1)sin2(πx) is equal to :Aπ26\dfrac{\pi^2}{6}6π2Bπ23\dfrac{\pi^2}{3}3π2Cπ22\dfrac{\pi^2}{2}2π2Dπ2\pi^2π2Check answerJust show me the answer
