Medium· Negation, conjunction, disjunction· +4 / −1Negation of the Boolean statement (p∨q)⇒((∼r)∨p)(p\vee q)\Rightarrow\left((\sim r)\vee p\right)(p∨q)⇒((∼r)∨p) is equivalent to :Ap∧(∼q)∧rp\wedge(\sim q)\wedge rp∧(∼q)∧rB(∼p)∧(∼q)∧r(\sim p)\wedge(\sim q)\wedge r(∼p)∧(∼q)∧rC(∼p)∧q∧r(\sim p)\wedge q\wedge r(∼p)∧q∧rDp∧q∧(∼r)p\wedge q\wedge(\sim r)p∧q∧(∼r)Check answerJust show me the answer
