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Differential Equations: JEE Mains 2022 June 29 Shift 1

Medium· Homogeneous equations· +4 / −1

Let the solution curve of the differential equation

x\dfrac{dy}{dx}-y=\sqrt{y^2+16x^2}

,

y(1)=3

be

y=y(x)

. Then

y(2)

is equal to :

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