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Statistics: JEE Mains 2022 June 29 Shift 1

Easy· Variance and standard deviation· +4 / −1

Let the mean and the variance of

5

observations

x_1,x_2,x_3,x_4,x_5

be

\dfrac{24}{5}

and

\dfrac{194}{25}

respectively. If the mean and variance of the first

4

observations are

\dfrac72

and

a

respectively, then

(4a+x_5)

is equal to :

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