Vector Algebra: JEE Mains 2022 June 29 Shift 1

Easy· Cross product· +4 / −1
Let a⃗=αi^+3j^−k^\vec a=\alpha\hat i+3\hat j-\hat k, b⃗=3i^−βj^+4k^\vec b=3\hat i-\beta\hat j+4\hat k and c⃗=i^+2j^−2k^\vec c=\hat i+2\hat j-2\hat k where α,β∈R\alpha,\beta\in\mathbb R, be three vectors. If the projection of a⃗\vec a on c⃗\vec c is 103\dfrac{10}{3} and b⃗×c⃗=−6i^+10j^+7k^\vec b\times\vec c=-6\hat i+10\hat j+7\hat k, then the value of α+β\alpha+\beta is equal to :
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