Units and Measurements: JEE Mains 2024 1st Feb Shift 1

Easy· Errors in measurement· +4 / −1
For measuring resistivity, the relation R=ρlA=ρlπr2R=\rho\frac{l}{A}=\frac{\rho l}{\pi r^2} is used. Percentage error in resistance (RR), in length (ll) and in radius (rr) are given xx, yy and zz respectively. Find percentage error in resistivity ρ\rho.
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  • Previous-year question from JEE Mains 2024 1st Feb Shift 1.
  • Tagged easy difficulty.