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Electrochemistry: NEET 2022

Hard· Nernst Equation· +4 / −1
Find the EMF of the cell in which the following reaction takes place at 298 K:
Ni(s)+2Ag+(0.001 M)→Ni2+(0.001 M)+2Ag(s)\mathrm{Ni(s)+2Ag^+(0.001\,M)\rightarrow Ni^{2+}(0.001\,M)+2Ag(s)}
(Given that Ecell∘=1.05E^\circ_{cell}=1.05 V, 2.303 RTF=0.059\dfrac{2.303\,RT}{F}=0.059 at 298 K)
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