Rotational Motion: NEET 2021

Medium· Equilibrium of a Rigid Body (Principle of Moments)· +4 / −1

A uniform rod of length

200\ \mathrm{cm}

and mass

500\ \mathrm{g}

is balanced on a wedge placed at

40\ \mathrm{cm}

mark. A mass of

2\ \mathrm{kg}

is suspended from the rod at

20\ \mathrm{cm}

and another unknown mass

m

is suspended from the rod at

160\ \mathrm{cm}

mark as shown in the figure. Find the value of

m

such that the rod is in equilibrium. (

g = 10\ \mathrm{m/s^2}

) Figure: a horizontal rod marked from 0 to 200 cm, supported on a wedge at the 40 cm mark, with a

2\ \mathrm{kg}

mass hanging at the 20 cm mark and the mass

m

hanging at the 160 cm mark. Question diagram

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