Work, Energy and Power: JEE Mains 2022 June 29 Shift 1

Easy· Work-energy theorem· +4 / −1
A particle of mass 500 g500\ \text{g} is moving in a straight line with velocity v=b x5/2v=b\,x^{5/2}. The work done by the net force during its displacement from x=0x=0 to x=4 mx=4\ \text{m} is: (Take b=0.25 m−3/2s−1b=0.25\ \text{m}^{-3/2}\text{s}^{-1})
Practise more Work, Energy and Power PYQs